Program 11TH in C++

PROBLEM STATEMENT :

input linked list is : 1->9->3->8->5->7->7

do you see any pattern in this input ?
odd placed nodes are in increasing order and even placed nodes are in decreasing order.
write a code that gives the the following linkedlist:
output linked list should be 1->3->5->7->7->8->9

?? can it be done inplace ?

SOLUTION :

#include <iostream.h>

#include <cstdio>

#include <list.h>

using namespace std;

void print(int arr[], int size)

{

list<int> li(arr,arr+size);

list<int> :: iterator it;

list<int> li1;

list<int> :: reverse_iterator it1;

cout<

//storing odd no elements in the new list and deleting the same from old list

for(it=li.begin(); it!=li.end(); it++)

{

li1.push_back(*it);

it=li.erase(it);

if(it!=li.end())

{

continue;

}

else

{

break;

}

}

//old list now contain the even places elements only and adding them from back to front in new list created above

for(it1=li.rbegin(); it1!=li.rend(); )

{

li1.push_back(*it1);

li.remove(*it1);

}

//displaying newly created list

for(it=li1.begin(); it!=li1.end(); it++)

{

cout<<*it<<" ";

}

}

int main()

{

int arr[]={1,9,3,8,5,7,7};

int arr1[]={1,9,4,6,7,3};

int arr2[]={2,5,6,4,9,3};

print(arr,sizeof(arr)/sizeof(int));

print(arr1,sizeof(arr1)/sizeof(int));

print(arr2,sizeof(arr2)/sizeof(int));

}